answer and explanation
this question requires us to determine the total energy required for the heating of ice to water at 80 degrees.
first we can use the specific heat equation which is
q = m x Cp x T
q - heat
m- mass
Cp - is specific heat
T- is the change in temperature
Cp of water is 4.185j/g deg Celcius
therefore
q = (3.50)(4.185)(80)
= 1171.8 J
but we also need to calculate the change from ice to water and we can use the latent heat formula
q = mL
L is the latent heat of fusion/vapourization of a substance
q = (3.50)( 334)
= 1169J
therefore the total energy needed is 1169 + 1171.8 = 2340.8 J or 2.34KJ
