The final pressure of the gas inside the ballon is 0.17 atm.
To solve this problem, we would need to use ideal gas equation.
This is a combination of the three major gas laws which are Boyle's law, Charles law and Pressure Law.
This is given as
[tex]\frac{p_1v_1}{t_1}=\frac{p_2v_2}{t_2}[/tex]we can define our variables
V1 = 1.2L
P1 = 1.1 atm
T1 = 25°C = (25 + 273.15)K = 298.15K
V2 = 6.7L
T2 = 75°C = (75 + 273.15)K = 348.15K
P2 = ?
Let's substitute the values into the equation above and solve for the final pressure
[tex]\begin{gathered} \frac{p_1v_1}{t_1}=\frac{p_2v_2}{t_2} \\ p_2=\frac{p_1v_1t_2}{v_2t_1} \\ p_2=\frac{1.1\times1.2\times348.15}{6.7\times298.15} \\ p_2=0.17\text{atm} \end{gathered}[/tex]The final pressure of the gas inside the ballon is 0.17 atm.
