Given the equation of the parabola:
[tex]y=\frac{1}{2}x^2-4[/tex]
We will graph the parabola as follows:
Specify the vertex then draw 2 points to the left of the vertex and 2 points to the right of the vertex
The vertex of the given parabola = (0, -4)
We will find the value of (y) when x = -4, -2, 2, 4
So,
When x = -4 ⇒ y = 4
When x = -2 ⇒ y = -2
The vertex when x = 0 ⇒ y = -4
When x = 2 ⇒ y = -2
When x = 4 ⇒ y = 4
So, the points on the left of the vertex are (-4, 4) and (-2, -2)
The points on the right of the vertex are (2, -2) and (4, -4)
the graph of the parabola will be as shown in the following figure:
