Given that the mass of train is
[tex]m=\text{ }8.12\times10^6\text{ kg}[/tex]
The deceleration of the train is
[tex]\begin{gathered} a\text{ = -104 km/h} \\ =-104\times\frac{5}{18} \\ =\text{ -28.88 m/s} \end{gathered}[/tex]
The braking force can be calculated by the formula
[tex]F=ma[/tex]
Substituting the values, the braking force will be
[tex]\begin{gathered} F=8.12\times10^6\times(-28.88) \\ =2.348\times10^8\text{ N} \end{gathered}[/tex]
Thus, the braking force is 2.348 x 10^8 N.
