Notice that the line passes through the point (0,1) and the point (3,-1). Then, we have the following:
[tex]\begin{gathered} y-\text{intercept: (0,1)} \\ \text{slope:} \\ m=\frac{y_2-y_1}{x_2-x_1} \\ \Rightarrow m=\frac{-1-0}{3-0}=-\frac{1}{3} \\ m=-\frac{1}{3} \end{gathered}[/tex]
now we can find the equation of the line using the slope and the y-intercept:
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ \Rightarrow y-1=-\frac{1}{3}(x-0) \\ \Rightarrow y=-\frac{1}{3}x+1 \end{gathered}[/tex]
therefore, the equation of the line is y=-1/3x+1
