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Find the starting value and the base for the exponential function f(x)=kb^x that passes through the two points:(0,3) and (2,12).The starting value k is: AnswerThe base b is: Answer

Find the starting value and the base for the exponential function fxkbx that passes through the two points03 and 212The starting value k is AnswerThe base b is class=

Respuesta :

The exponential equation given is,

[tex]f(x)=kb^x[/tex]

Given the points

[tex](0,3)\text{ and (2,12)}[/tex]

Therefore, the values for k and b will be resolved graphically.

Let us now plot the graph using a graphical calculator

From the graph,

[tex]\begin{gathered} y_1=f(x) \\ a=k=3 \\ b=2 \end{gathered}[/tex]

Final answers

[tex]\begin{gathered} k=3 \\ b=2 \end{gathered}[/tex]

Ver imagen AvereighD158158

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