Given,
The coordinate that lie on the line is (-4, -3).
The equation of line is y = 3/4x-1.
The standard equation of line is,
[tex]y=mx+c[/tex]Here, m is the slope of the line.
On comparing, the slope of the line y = 3/4x-1 with the standard equation of line then m = 3/4.
The relation of two perpendicular line is,
[tex]\begin{gathered} m_1\times m_2=-1_{} \\ \frac{3}{4}\times m_2=-1 \\ m_2=\frac{-4}{3} \end{gathered}[/tex]The equation of line passing through the point (-4,-3) and perpendicular to line y = 3/4x-1 is,
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-(-3)=\frac{-4}{3}(x-(-4)) \\ y+3=\frac{-4}{3}(x+4) \\ 3y+9=-4x-16 \\ 3y=-4x-25 \\ y=\frac{-4x-25}{3} \end{gathered}[/tex]Hence, the equation of line perpendicular to y = 3/4x-1 is y = (-4x-25)/3.
