D)
To find the probability of selling 25 cheesecakes:
It is impossible to find the probability of selling 25 cheesecakes.
So,
P(x=25)=0
The probability of selling 25 cheesecakes is 0.
E)
To find the probability of selling at most 10 cheesecakes:
That is,
[tex]\begin{gathered} P(x\leq10)=P(x=0)+P(x=5)+P(x=10) \\ =0.1+0.23+0.04 \\ =0.37 \end{gathered}[/tex]
Therefore, the probability of selling at most 10 cheesecakes is 0.37.
F)
To find the expected number of cheesecakes sold on any given day using the discrete probability distribution:
[tex]\begin{gathered} \sum ^5_{i\mathop=1}x_ip_i=x_1p_1+x_2p_2+x_3p_3+x_4p_4+x_5p_5 \\ =0(0.1)+5(0.23)+10(0.04)+15(0.46)+20(0.17)_{}_{}_{} \\ =0+1.15+0.4+6.9+3.4 \\ =11.85 \end{gathered}[/tex]
Hence, the expected number of cheesecakes sold on any given day using the discrete probability distribution is 11.85.
