Answer:
0.96moles
Explanations:
Given the reaction between Magnessium and silver nitrate expressed as:
[tex]Mg(s)+2AgNO_3(aq)\rightarrow Mg(NO_3)_2(aq)+2Ag(s)[/tex]
Given the following parameter
Moles of Magnessium at the start = 0.480moles
According to stoichiometry, 1mole of magnessium produce 2 moles of silver. Hence the moles of silver that is produced if 0.48moles of Mg reacted is given as:
[tex]\begin{gathered} mole\text{ of Ag = 2}\times0.48moles \\ mole\text{ of Ag =}0.96moles \end{gathered}[/tex]
Hence the moles of silver that will produced is 0.96moles
