Answer:
f(x) = (2x + 3)(2x + 1)
Explanation:
The form that best reveals the zeros of the function is:
f(x) = (x - a)(x - b)
Where a and b are the zeros of the function.
So, we need to apply the distributive property as:
[tex]\begin{gathered} f(x)=2(2x^2+4x)+3 \\ f(x)=2\cdot2x^2+2\cdot4x+3 \\ f(x)=4x^2+8x+3 \end{gathered}[/tex]
Then, we can factorize the quadratic function as:
[tex]f(x)=(2x+3)(2x+1)[/tex]
So, now we can identify the zeros of the function if we solve the following equation:
[tex]\begin{gathered} f(x)=(2x+3)(2x+1)=0 \\ 2x+3=0\rightarrow x=-\frac{3}{2} \\ or \\ 2x+1=0\rightarrow x=-\frac{1}{2} \end{gathered}[/tex]
Therefore, the form that best reveals the zeros in the function is:
f(x) = (2x + 3)(2x + 1)
