32.6 grams
Given the reaction between aluminium and ferric oxide as shown;
[tex]2Al+3FeO\rightarrow Al_2O_3+3Fe[/tex]Determine the moles of Aluminium
Mole = Mass/Molar mass
Mole = 10.5/26.98
Mole of Al = 0.3892moles
According to stoichiometry, 2moles of aluminium produced 3 moles of Iron, the moles of Iron needed is given as:
moles of Fe = 3/2 * 0.3892
moles of Fe = 0.5838moles
Determine the mass of iron
Mass of Fe = moles * molar mass
Mass of Fe = 0.5838 * 55.845
Mass of Fe = 32.6grams
Hence mass of iron that can be produced from 10.5 grams of aluminium is 32.6 grams
