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The student Fun Club plans to go to the movies. At the matinee, tickets cost $6 and popcorn is $3. At evening shows, tickets cost $9 and popcorn is $4. The Fun Club attends a matinee and spends less than $60, and then attends an evening show and spends more than $36. If they purchased the same number of tickets and popcorns at each show, which of the following is a possible solution for the number of tickets and popcorns purchased?3 tickets and 2 popcorns7 tickets and 5 popcorns9 tickets and 3 popcorns8 tickets and 6 popcorns

Respuesta :

MAtine:

each ticket = $6

Each popcorn = $3

Evening:

Each ticket = $9

Each popcorn = $4

Number of tickets = t

Number of popcorns = p

Fun club attends at matinee, spends less than $60

6t + 3p < 60

Then attends an evening show and spends more than $36

9t + 4p > 36

The system of inequations:

6t + 3p < 60

9t + 4p > 36

Graph each and find the solution

6x + 3y < 60

9x + 4y > 36

Where both areas overlap is the solution:

Answer: 7 tickets and 5 popcorns

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