You have to calculate the probability of obtaining an odd number after rolling the die and obtaining tail after tossing a coin, symbolically:
[tex]P(O\cap T)[/tex]Where
"O" represents the event " rolling an odd number"
"T" represents the event "tossing a coin and obtaining tail"
The events are independent, which means that the intersection between both events is equal to the product of the individual probability of each event:
[tex]P(O\cap T)=P(O)\cdot P(T)[/tex]So, first, we have to calculate the probabilities of "rolling an odd number" P(O) and "tossing a coin and obtaining tail" P(T)
-The die is six-sided and numbered from 1 to 6, assuming that each possible outcome has the same probability, we can calculate the probability of rolling one number (N) as follows:
[tex]\begin{gathered} P(N\text{)}=\frac{\text{favorable outcomes}}{total} \\ P(N)=\frac{1}{6} \end{gathered}[/tex]The possible outcomes when you roll a die are {1, 2, 3, 4, 5, 6}
Out of these six numbers, three are odd numbers {1, 3, 5}, this is the number of favorable outcomes of the event "O", and the probability can be calculated as follows:
[tex]\begin{gathered} P(O)=\frac{\text{favorable outcomes}}{total} \\ P(O)=\frac{3}{6}=\frac{1}{2} \end{gathered}[/tex]So, the probability of rolling an odd number is P(O)=1/2
-When you toss a coin, there are two possible outcomes: "Head" and "Tail", assuming that both outcomes are equally possible.
For the event "toss a coin and obtain tail" there is only one favorable outcome out of the two possible ones, so the probability can be calculated as:
[tex]\begin{gathered} P(T)=\frac{\text{favorable outcomes}}{total} \\ P(T)=\frac{1}{2} \end{gathered}[/tex]The probability of tossing a coin and obtaining a tail is P(T)=1/2
Once calculated the individual probabilities you can determine the asked probability:
[tex]P(O\cap T)=P(O)\cdot P(T)=\frac{1}{2}\cdot\frac{1}{2}=\frac{1}{4}[/tex]