Take into account that the vertical distance traveled by the acorn can be calculated by using:
[tex]h=\frac{1}{2}gt^2[/tex]where,
g: gravitational acceleration constant = 9.8m/s^2
t: time acorn takes to hit the ground = 2.0s
h: height at which acorn is initially = ?
Replace the given values of the parameters into the previous formula and simplfiy:
[tex]h=\frac{1}{2}(9.8\frac{m}{s^2})(2.0s)^2=19.6m[/tex]Hence, the acorn was released from a high of 19.6m above the ground.
The velocity just after acorn hits the ground is given by:
[tex]\begin{gathered} v=gt \\ v=(9.8\frac{m}{s^2})(2.0s)=19.6\frac{m}{s} \end{gathered}[/tex]Hence, the speed is 19.6 m/s
