PART B
The probability is 1/2
STEP - BY - STEP EXPLANATION
What to find?
The probability of identical twins given that the twins consists of two boys.
Let A be the event of identical twins.
Let B be the event of having two boys as twins.
From the table given;
P(A) = 2/38
P(B)= 2/38
Recall the formula for a condititional probabibility
[tex]P(A\text{ \backslash{}B)=}\frac{P(A\text{ n }B)}{P(B)}[/tex]
Note that:
P(A n B) =1/38
[tex]P(A\text{ \backslash B) =}\frac{\frac{1}{38}}{\frac{2}{38}}[/tex][tex]=\frac{1}{38}\times\frac{38}{2}[/tex][tex]=\frac{1}{2}[/tex]
Therefore, the probability of identical twins given that the twins consists of two boys is 1/2
