We are asked to determine the area of the given figure. The figure is composed of two semi-circles and a rectangle, therefore, the total area of the figure is:
[tex]A=A_s+A_r+A_s[/tex]The area of the semicircle is given by:
[tex]A_s=\frac{1}{8}\pi D^2[/tex]Where "D" is the diameter. Replacing the values we get:
[tex]A_s=\frac{1}{8}(3.14)(70m)^2[/tex]Solving the operations:
[tex]A_s=1923.25m^2[/tex]Now we determine the area of the rectangle using the following formula:
[tex]A_r=wh[/tex]Where "w" and "h" are the dimensions of the rectangle. Replacing the values we get:
[tex]\begin{gathered} A_r=(98m)(70m) \\ A_r=6860m^2 \end{gathered}[/tex]Now we replace the values in the formula for the total area:
[tex]A=1923.25m^2+6860m^2+1923.25m^2[/tex]Solving the operations:
[tex]A=10706.5m^2[/tex]