From the given linear graph, we would write out the co-ordinates of the points A and B first in the form of (x,y).
Thus, we have:
[tex]\begin{gathered} A(-6,-4) \\ B(-3,3) \end{gathered}[/tex]
The mid-point of a line segment;
[tex]\begin{gathered} A(x_1,y_1)\text{ and} \\ B(x_2,y_2) \end{gathered}[/tex]
is given as:
[tex](\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]
Thus, we have:
[tex]\begin{gathered} (\frac{-6+(-3)}{2},\frac{-4+3}{2}) \\ (\frac{-6-3}{2},-\frac{1}{2}) \\ (\frac{-9}{2},-\frac{1}{2}) \\ (-4.5,-0.5) \end{gathered}[/tex]
Hence, the midpoint of the line segment AB is: ( -4.5, -0.5)
