Since PM=PN
And
[tex]LM\perp MN[/tex]While
[tex]MN\perp ON[/tex]We can assume that
[tex]\begin{gathered} LN=OM\text{ and bisect each other} \\ \text{Therefore,} \\ PM=OP\text{ and }PN=LP \end{gathered}[/tex]Then we can conclude that
[tex]\begin{gathered} LP=PO\text{ ( Isosceles triangle theorem)} \\ \angle\text{MPL}=\angle NPO(\text{ Vertically opposite angles)} \\ \text{hence,} \\ \Delta MPL=\Delta NPO(By\text{ sides angle side)} \end{gathered}[/tex]Therefore,
The correct answer IS OPTION C
