Given:
mean, u = 0
standard deviation σ = 1
Let's determine the following:
(a) Probability of an outcome that is more than -1.26.
Here, we are to find: P(x > -1.26).
Apply the formula:
[tex]z=\frac{x^{\prime}-u}{\sigma}[/tex]
Thus, we have:
[tex]\begin{gathered} P(x>-1.26)=\frac{-1.26-0}{1} \\ \\ P(x>-1.26)=\frac{-1.26}{1}=-1.26 \end{gathered}[/tex]
Using the standard normal table, we have:
NORMSDIST(-1.26) = 0.1038
Therefore, the probability of an outcome that is more than -1.26 is 0.1038
(b) Probability of an outcome that
