We will have the following:
[tex]\begin{gathered} W\ast d=\frac{1}{2}mv_f^2-\frac{1}{2}mv_i^2 \\ \\ \end{gathered}[/tex]Then, we will have that:
[tex]\begin{gathered} (25N)(5m)=\frac{1}{2}(10kg)v_f^2-\frac{1}{2}(10kg)(0m/s){}2 \\ \\ \Rightarrow125N\ast m=(5kg)v_f^2\Rightarrow v_f^2=\frac{25N\ast m}{kg} \\ \\ \Rightarrow v_f=5m/s \end{gathered}[/tex]So, the final velocity of the mass after it has moved 5 meters is 5m/s.
