Given the phrase:
-3 times r is at least 33
Let's translate the given phrase into an inequality.
• Part A.
Let's figure out the inequality in steps.
-3 times r is written as:
-3r
-3 times s is at least 33 means that -3r is greater than or equal to 33.
Hence, we have the inequality:
[tex]-3r\ge33[/tex]• Part B.
Let's solve the inequality for r.
To solve for r, divide both sides of the inequality by -3:
[tex]\begin{gathered} \frac{-3r}{-3}\ge\frac{33}{-3} \\ \\ r\le-11 \end{gathered}[/tex]• Part C.
Let's express the solution in interval notation.
Here, the solution is:
[tex]r\le-11[/tex]It means s must be less than or equal to 11.
Therefore, the solution in interval notation is:
[tex](-\infty,-11\rbrack[/tex]ANSWER:
• A) -3r ≥ 33
• B) r ≤ -11
• C) (-∞, -11]
