For 97.1 seconds, a remote-controlled helicopter flew at an altitude of 3 meters and a constant velocity of 19.0 meters per second to the west. During this time, how far did the helicopter fly?

Respuesta :

The relationship between time, distance and velocity is:

[tex]v=\frac{d}{t}[/tex]

In this case, we need to find the distance, d

We can solve for d:

[tex]v=\frac{d}{t}\Rightarrow d=v\cdot t[/tex]

The velocity of flight is v = 19 m/s and the time of flight is t = 97.1s

Then:

[tex]d=19\frac{m}{s}\cdot97s[/tex][tex]d=1844.9m[/tex]

The answer is 1844.9m