Given that:
- The seeds cost is 40$ per acre for corn.
- The seeds cost is 30$ per acre for soybeans.
- The farmer wants to spend no more than $2400.
• Let be "x" the number of acres of seeds for corn and "y" the number of acres of seeds for soybeans.
You know that the total amount of money has to be less than or equal to $2400. Therefore, you can write the following Linear Inequality to represent that situation:
[tex]40x+30y\leq2400[/tex]You can rewrite it in another form by solving for "y":
[tex]\begin{gathered} 30y\leq-40x+2400 \\ \\ y\leq\frac{-40x}{30}+\frac{2400}{30} \end{gathered}[/tex][tex]y\leq-\frac{4}{3}x+80[/tex]Since the number of acres cannot be negative:
[tex]\begin{gathered} x\ge0 \\ y\ge0 \end{gathered}[/tex]• You can identify that the boundary line is:
[tex]y=-\frac{4}{3}x+80[/tex]It is written in Slope-Intercept Form:
[tex]y=mx+b[/tex]Where "m" is the slope and "b" is the y-intercept.
In this case, you can identify that the y-intercept is:
[tex]b=80[/tex]In order to find the x-intercept, substitute this value of "y" into the equation and solve for "x" (because the y-value is zero when the line intersects the x-axis):
[tex]y=0[/tex]Then, you get:
[tex]0=-\frac{4}{3}x+80[/tex][tex]\frac{(-80)(3)}{-4}=x[/tex][tex]x=60[/tex]You can identify that the symbol of the inequality is:
[tex]\leq[/tex]It indicates that the line must be solid and the shaded region must be below the boundary line.
Knowing all this information, you can graph the inequality on the Coordinate Plane (Remember that the values of the variables must be greater than or equal to zero. Then, you must shade with a different color the region in which "x" and "y" are greater than or equal to zero).
Hence, the answer is:
- Linear Inequality:
[tex]40x+30y\leq2400[/tex]- Nonnegative restrictions:
[tex]\begin{gathered} x\ge0 \\ y\ge0 \end{gathered}[/tex]- Graph:
