Answer:
Explanation:
Given:
To determine the area of the portion of the triangle that lies outside of the circle but within the triangle, we find the areas of triangle and circle first:
For the triangle, we use the formula:
A=1/2bh
where:
b=base
h=height
We plug in what we know:
[tex]\begin{gathered} A=\frac{1}{2}bh \\ =\frac{1}{2}(20ft)(20ft) \\ =\frac{1}{2}(400ft^2) \\ \text{Calculate} \\ A=200ft^2 \end{gathered}[/tex]
Next, we solve for the area of the circle using the given formula:
A=πr^2
where:
r=radius
So,
[tex]\begin{gathered} A=\pi r^2 \\ =\pi(6ft)^2 \\ \text{Calculate} \\ A=113.1ft^2 \end{gathered}[/tex]
Then, to find the area of the portion of the triangle that lies outside of the circle but within the triangle:
Area of the portion = Area of the Triangle - Area of the Circle
We plug in what we know:
[tex]\begin{gathered} \text{ }=200ft^2-113.1ft^2 \\ \text{Area of the portion = }86.9ft^2 \end{gathered}[/tex]
Therefore, the answer is 86.9 ft^2.
