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The vertices of ABCDE are A(-6,0), B(-3,0), C(0, -3), D(-3,-6), and E(-6, -3). Find the vertices of the image after a translation using the rule (x,y) - (x + 9, y-6) and a dilation with a scale factor of 4s centered at the origin.

Respuesta :

Vertices of new image: A' = (12, -24)

B' = (24, -24)

C' = (36, -36)

D' = (24, -48)

E = (12, -36)

Explanation:

A(-6,0), B(-3,0), C(0, -3), D(-3,-6), and E(-6, -3)

A translation of (x + 9, y-6)

A becomes A'

A' = (-6 + 9, 0 - 6) = (3, -6)

B(-3,0)

B becomes B'

B' = (-3+9, 0 - 6) = B' (6, -6)

C(0, -3)

C becomes C'

C' = (0+9, -3-6) = C' (9, -9)

D(-3,-6)

D becomes D'

D' = (-3+9, -6-6) = (6, -12)

E(-6, -3)

E becomes E'

E' = (-6+9, -3-6) = (3, -9)

A dilation with scale factor of 4, we multiply the cooordinates of the alphabeths with prime with 4.

Vertices of new image:

A' = 4(3, -6) = (12, -24)

B' = 4(6, -6) = (24, -24)

C' = 4(9, -9) = (36, -36)

D' = 4(6, -12) = (24, -48)

E = 4(3, -9) = (12, -36)

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