[tex]\begin{gathered} 9\frac{4}{8}-\frac{7}{8} \\ =\frac{76}{8}-\frac{7}{8} \end{gathered}[/tex][tex]\frac{76}{8}-\frac{7}{8}=\frac{76-7}{8}=\frac{69}{8}\text{ or 8}\frac{5}{8}[/tex]
for 2nd question
[tex]\begin{gathered} 9\frac{4}{8}-5\frac{1}{8}=\frac{76}{8}-\frac{41}{8} \\ =\frac{76-41}{8}=\frac{35}{8}\text{ or 4}\frac{3}{8} \end{gathered}[/tex]
for 3rd question,
[tex]\begin{gathered} 9\frac{4}{8}-3\frac{5}{8}=\frac{76}{8}-\frac{29}{8} \\ =\frac{76-29}{8}=\frac{47}{8}\text{ or 5}\frac{7}{8} \end{gathered}[/tex]
for 4th question,
[tex]\begin{gathered} 5\frac{1}{8}-3\frac{5}{8}=\frac{41}{8}-\frac{29}{8} \\ =\frac{41-29}{8}=\frac{12}{8}=\frac{3}{2}\text{ or 1}\frac{1}{2} \end{gathered}[/tex]
