Answer:
1 second
Explanation:
The equation that models the path of the ball is given below:
[tex]h\mleft(t\mright)=-16t^2+32t+4[/tex]
To determine how long it takes the ball takes to reach its maximum height, we find the equation of the line of symmetry.
[tex]\begin{gathered} t=-\frac{b}{2a},a=-16,b=32 \\ t=-\frac{32}{2(-16)} \\ =-\frac{32}{-32} \\ t=1 \end{gathered}[/tex]
Thus, we see that it takes the ball 1 second to reach its maximum height.
