The sum of 3 times a number and another number is 34. Five times the first number minus the other number is 38. What are the two numbers. The numbers are 3 and 11. The numbers are 9 and 7.
Let
x -----> first number
y -----> another number
we have that
3x+y=34 -------> equation A
5x-y=38 -----> equation B
solve by elimination
Adds the equations
so
8x=72
x=72/8
x=9
substitute
3(9)+y=34
y=34-27
y=7
therefore
