Explanation:
Given the following reaction.
NO (g) + 1/2 O₂ (g) <---> NO₂ (g)
We have to find the relationship between its Kc and Kp.
The Kp can be calculated from the Kc using the following expression.
Kp = Kc * (R*T)^(Δn)
Where Δn is the sum of the coefficients of the products minus the sum of the coefficients of the reactants. So Δn will be equal to:
Δn = Σ n of products - Σ n of reactants
Δn = 1 - (1 + 1/2)
Δn = -1/2
So we can say that:
Kp = Kc * (R*T)^(Δn)
Kp = Kc * (R*T)^(-1/2)
Kc = Kp * (R*T)^(1/2)
Answer: Kc = Kp * (R*T)^(1/2)
