Explanation:
The function is given below as
[tex]f(x)=x^2+4[/tex]
Find
[tex]\begin{gathered} f(0) \\ put\text{ }x=0 \\ f(0)=(0)^2+4 \\ f(0)=4 \end{gathered}[/tex][tex]\begin{gathered} f(\frac{1}{2}) \\ put\text{ }x=\frac{1}{2} \\ f(\frac{1}{2})=(\frac{1}{2})^2+4 \\ f(\frac{1}{2})=\frac{1}{4}+4 \\ f(\frac{1}{2})=\frac{17}{4} \end{gathered}[/tex][tex]\begin{gathered} f(-1) \\ put\text{ }x=-1 \\ f(-1)=(-1)^2+4 \\ f(-1)=1+4 \\ f(-1)=5 \end{gathered}[/tex]
Hence,
The final answer is
[tex]4,\frac{17}{4},5[/tex]
The FIRST OPTION is the correct answer
