Solution:
Given the circle with its radius, r;
[tex]r=11cm[/tex]
Thus, the circumference, C, of a circle is;
[tex]C=2\pi r[/tex]
Then;
[tex]\begin{gathered} C=2\pi(11)cm \\ \\ C=22\pi cm \end{gathered}[/tex]
ANSWER:
[tex]C=22.0\pi cm[/tex]
Also, the area, A, of the circle is;
[tex]A=\pi r^2[/tex]
Then;
[tex]\begin{gathered} A=\pi(11)^2 \\ \\ A=121\pi cm^2 \end{gathered}[/tex]
ANSWER:
[tex]A=121.0\pi cm^2[/tex]
