Consider a system of a cliff diver and the earth. The gravitational potential energy of the system decreases by 26,500 J as the diver drops to the water from a height of 33.0 m. Determine her weight in newtons.

Respuesta :

Given data:

* The change in gravitational potential energy is 26500 J.

* The change in height of the diver is 33.0 m.

Solution:

The change in gravitational potential energy in terms of change in height of the diver is,

[tex]dU=mg\times dh[/tex]

where m is the mass of diver, g is the acceleration due to gravity, dh is the change in height, and dU is the change in gravitational potential energy,

Substituting the known values,

[tex]\begin{gathered} 26500=mg\times33 \\ mg=\frac{26500}{33} \\ mg=803.03\text{ N} \end{gathered}[/tex]

The weight of the diver is,

[tex]\begin{gathered} W=mg \\ W=803.03\text{ N} \end{gathered}[/tex]

Thus, weight of the diver is 803.03 N.