We have a line with equation:
[tex]y-5=\frac{9}{7}(x+4)[/tex]The expression of the line is the slope-point form, that is:
[tex]y-y_0=m(x-x_0)[/tex]where (x0,y0) is a point of the line and m is the slope.
As in this case, m = 9/7, then the slope is 9/7.
By inspecting the equation, the graph of the line has a slope of 9/7.
We also know that (x0,y0) = (-4, 5), that belong to the line.
By inspecting the equation the graph of the line passes through the point (-4, 5).
To find the value of y(3) we replace x with the value 3:
[tex]\begin{gathered} y-5=\frac{9}{7}(3+4)=\frac{9}{7}\cdot7=9 \\ y-5=9 \\ y=9+5 \\ y=14 \end{gathered}[/tex]The value of y(3) is 14. The point is (3, 14).
