Respuesta :
Answer:
5.57 grams
Explanations:
Given the reaction between sodium and oxygen expressed as:
[tex]4Na(s)+O_2(g)\rightarrow2Na_2O(s)[/tex]Given the following parameters
Mass of sodium = 16.0g
Determine the moles of sodium
[tex]\begin{gathered} moles\text{ of Na}=\frac{mass}{molar\text{ mass}} \\ moles\text{ of Na}=\frac{16}{23} \\ moles\text{ of Na}=0.6957moles \end{gathered}[/tex]According to stoichiometry, 4 moles of sodium reacts with 1 mole of oxygen, the moles of oxygen that reacted is given as;
[tex]\begin{gathered} moles\text{ of O}_2=\frac{0.6957}{4} \\ moles\text{ of O}_2=0.1739moles \end{gathered}[/tex]Determine the mass of oxygen that reacted
[tex]\begin{gathered} mass\text{ of O}_2=mole\times molar\text{ mass} \\ mass\text{ of O}_2=0.1739\times32 \\ mass\text{ of O}_2=5.57grams \end{gathered}[/tex]Hence the mass of oxygen that reacted is 5.57 grams
