Given data
*The given height is h = 0.45 m
*The value of the acceleration due to gravity is g = 9.8 m/s^2
The formula for the minimum speed (v) required for the cart to reach the top of the slope is given by the conservation of energy as
[tex]\begin{gathered} U_k=U_p \\ \frac{1}{2}mv^2=mgh \\ v=\sqrt[]{2gh} \end{gathered}[/tex]
Substitute the known values in the above expression as
[tex]\begin{gathered} v=\sqrt[]{2\times9.8\times0.45} \\ =2.96\text{ m/s} \end{gathered}[/tex]
Hence, the minimum speed (v) required for the cart to reach the top of the slope is v = 2.96 m/s
