Lets take 2 pair of points from the table:
[tex]\begin{gathered} (x_1,y_1)=(0,4) \\ (x_2,y_2)=(2,10) \end{gathered}[/tex]
The equation of line is y = mx + b
Where
m is slope
b is y-intercept
Let's find the slope (m):
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{10-4}{2-0} \\ m=\frac{6}{2} \\ m=3 \end{gathered}[/tex]
So, the equation becomes:
[tex]y=3x+b[/tex]
Let's plug in the first point (x, y) = (0,4) to find b:
[tex]\begin{gathered} y=3x+b \\ 4=3(0)+b \\ 4=0+b \\ b=4 \end{gathered}[/tex]
Final Equation of the line:
[tex]y=3x+4[/tex]
