Answer:
The equation is given below as
[tex]2y=5x-10[/tex]
Concept:
To calculate the value of y when x=0, we will substitute the x=0 in the equation above and solve for y
By substituting the values, we will have
When x=0
[tex]\begin{gathered} 2y=5x-10 \\ 2y=5(0)-10 \\ 2y=-10 \\ \frac{2y}{2}=-\frac{10}{2} \\ y=-5 \\ (0,-5) \end{gathered}[/tex]
When x=1
[tex]\begin{gathered} 2y=5x-10 \\ 2y=5(1)-10 \\ 2y=5-10 \\ 2y=-5 \\ \frac{2y}{2}=-\frac{5}{2} \\ y=-2.5 \\ (0,-2.5) \end{gathered}[/tex]
When x=2
[tex]\begin{gathered} 2y=5x-10 \\ 2y=5(2)-10 \\ 2y=10-10 \\ 2y=0 \\ \frac{2y}{2}=\frac{0}{2} \\ y=0 \\ (2,0) \end{gathered}[/tex]
When x=3
[tex]\begin{gathered} 2y=5x-10 \\ 2y=5(3)-10 \\ 2y=15-10 \\ 2y=5 \\ \frac{2y}{2}=\frac{5}{2} \\ y=2.5 \\ (3,2.5) \end{gathered}[/tex]
When x=4
[tex]\begin{gathered} 2y=5x-10 \\ 2y=5(4)-10 \\ 2y=20-10 \\ 2y=10 \\ \frac{2y}{2}=\frac{10}{2} \\ y=5 \\ (4,5) \end{gathered}[/tex]
Hence,
By graphing using the ordered pairs below, we will have
[tex]\begin{gathered} (2,0) \\ (0,-5) \end{gathered}[/tex]
