To determine if the point is a solution or not, we have to substitute the x-value and see if the y-value is correct:
*For x=5
[tex]\begin{gathered} -2y+5=8 \\ -2y=8-5 \\ y=-\frac{3}{2} \\ y=-1.5 \end{gathered}[/tex]
For x=2
[tex]\begin{gathered} -2y+2=8 \\ -2y=8-2 \\ y=-\frac{6}{2} \\ y=-3 \end{gathered}[/tex]
For x=-1
[tex]\begin{gathered} -2y-1=8 \\ -2y=8+1 \\ y=-\frac{9}{2} \\ y=-4.5 \end{gathered}[/tex]
For x=-3
[tex]\begin{gathered} -2y-3=8 \\ -2y=8+3 \\ y=\frac{11}{-2} \\ y=-5.5 \end{gathered}[/tex]
Then, the point that is NOT a solution for the equation is D. (-3, 2). The solution for x=-3 is -5.5.
