The formula for the area of a trapezoid is:
[tex]A=\frac{1}{2}h(b_1+b_2)[/tex]
Where h is the height and b_1, b_2 are the parallel lines or bases
1) We have trapezoid with:
[tex]\begin{gathered} b_1=5yd \\ b_2=23yd \\ h=12yd \end{gathered}[/tex]
Using the formula:
[tex]A=\frac{1}{2}12yd(5yd+23yd)=168yd^2[/tex]
2) The dimensions of trapezoid 2 are:
[tex]\begin{gathered} b_1=1.1cm \\ b_2=3.4cm \\ h=2cm \end{gathered}[/tex]
Using the formula:
[tex]A=\frac{1}{2}2cm(1.1cm+3.4cm)=1cm\cdot4.5cm=4.5cm^2[/tex]
3) The dimensions are:
[tex]\begin{gathered} b_1=17.75m \\ b_2=10.25m \\ h=8m \end{gathered}[/tex]
Using the formula:
[tex]A=\frac{1}{2}8m(17.75m+10.25m)=4m\cdot28m=112m^2[/tex]
