The probability that the average fracture strength of 100 randomly selected pieces will be equal to 33.19%.
In order to find the probability first we find the Z score. The Z score related the standard deviation and the mean of any data as
Z = X - μ/σ where Z is the Z score, X is the random variable, μ is the mean and σ is the standard deviation.
The standard deviation of the randomly selected 100 variables will be given as
s = σ/√n where n = 100 and σ = 2
s = 2/√100
s = 0.2
Now, the Z score for this data will be
Z = X - μ/s where X = 13.8, and μ = 13.5 and the value of s = 0.2
Z = 13.8 - 13.5/0.2
Z = 1.5
Now, for Z = 1.5 the p value will be 0.66807
The probability will be P = 1 - 0.66807 = 0.33193 that is 33.19%
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