Maya drove on the mountains for her trip. Due to traffic, her average rate of miles per hour was faster at the time of coming back to her home than going on her trip. Thus, The distance between where she lives and the mountains is
288 miles .
Let's consider that Maya live x miles from the mountains.
Let her rate to mountains be y miles/h.
we have given that
Driveing time taken by Maya going from home to trip location= 9 hours due to traffic
total return time taken by her = 4 hours
average rate = 40 miles/hour
Using rate formula,
Rate = distance/time
=> distance (d) = rate (r) × time (t)
so, x/y = 9
=> x=9y --(1)
Return trip 4 hours then rate = y+40
=> x/(y+40) =4 --(2)
using Substitution method, x= 3 substitute in (2)
=> 9y/(y+40)=4
=> 9y=4y+160
=> 9y-4y=160
=> 5y=160
=> y= 160/5
=> y=32
Now, x=9y
x=9×32= 288 miles
Hence, distance to the mountain is 288 miles.
To learn more about rate of displacement, refer:
https://brainly.com/question/12619606
#SPJ4
Complete question:
Maria drove to the mountains last weekend. There was heavy traffic on the way there, and the trip took 9 hours. When Maria drove home, there was no traffic and the trip only took 4 hours. If her average rate was 40 miles per hour faster on the trip home, how far away does Maria live from the mountains?
Do not do any rounding.
