The probability that exactly 2 of them are the deluxe model =0.474
given that
there is a shipment of 15 televisions contains 6 regular and 9 deluxe models
now 3 cartons are selected at random
C(15,3) =[tex]\frac{15!}{(15-3)!3!}[/tex]
C(15,3) = [tex]\frac{13*14*15}{3*2*1}[/tex]
C(15,3) = 455
2 out of 9 deluxe models be picked
C(9,2) = [tex]\frac{9!}{(9-2)!2!}[/tex]
C(9,2) = [tex]\frac{8*9}{2*1}[/tex]
C(9,2) = 36
Each of these can be matched with 1 of 6 regular models
36 × 6 = 216
the probability that exactly 2 of them are the deluxe model
= [tex]\frac{216}{455}[/tex]
=0.474
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