The combustion of ammonia in the prescne of excess oxygen yield no2 and h2o. 0.119 grams of no2 are produced when 43.9mg of ammonia burn.
Molar mass of NH3 = 1*MM(N) + 3*MM(H)
= 1*14.01 + 3*1.008
= 17.034 g/mol
mass of NH3 = 0.0439 g
mol of NH3 = (mass)/(molar mass)
= 0.0439/17.034
= 2.577*10^-3 mol
From balanced chemical reaction, we see that
when 4 mol of NH3 reacts, 4 mol of NO2 is formed
mol of NO2 formed = moles of NH3
= 2.577*10^-3 mol
Molar mass of NO2 = 1*MM(N) + 2*MM(O)
= 1*14.01 + 2*16.0
= 46.01 g/mol
mass of NO2 = number of mol * molar mass
= 2.577*10^-3*46.01
= 0.119 g
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