Find the missing side and angle measures in triangle ABC. Round your answers to the neFind the missing side and angle measures in triangle ABC. Round your answers to the nearest tenth.arest tenth. Scalene triangle ABC with side AC labeled 23 and side BC labeled 15. Angle A measures 40 degrees. The measure of angle B is approximately . The measure of angle C is approximately . The length of side AB is approximately units.

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Answer:

  • B = 80.3°, C = 59.7°, AB = 20.2
  • B = 99.7°, C = 40.3°, AB = 15.1

Step-by-step explanation:

You want the solution to scalene triangle ABC with AC = 23, BC = 15, and ∠A = 40°.

Law of Sines

When two sides of a triangle are given, along with an angle not between them, the Law of Sines can be used to solve the triangle. It tells you ...

  sin(B)/AC = sin(C)/AB = sin(A)/BC

When the given angle is opposite the shortest given side, there are generally 2 solutions.

Application

  sin(B)/23 = sin(40°)/15 . . . . . fill in given values to find angle B

  B = arcsin(23/15·sin(40°)) = 80.3° or 99.7°

Angle C will have the value that makes up the difference from 180°:

  C = 180° -40° -{80.3°, 99.7°} = {59.7°, 40.3°}

The length of side AB can be found using the same Law of Sines proportion:

  AB = BC·sin(C)/sin(A) = 15/sin(40°)·sin({59.7°, 40.3°})

  AB = {20.2, 15.1}

The solutions are ...

  • B = 80.3°, C = 59.7°, AB = 20.2
  • B = 99.7°, C = 40.3°, AB = 15.1

Arguably, the second solution is not a "scalene" triangle. It is (nearly) isosceles. (See the comment below.)

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Additional comment

Since answers are requested to be rounded to tenths, both solutions are scalene triangles. If we rounded to integers, then only the first solution would be a scalene triangle.

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Ver imagen sqdancefan