Answer:
8
Step-by-step explanation:
Give a prime factorization consisting of two primes, with one of them cubed, you want to know the number of positive integer divisors.
Divisors
The number of divisors is the product of the exponents of the prime factorization, each increased by 1.
Application
Your number is ...
n = (a^3)(b^1)
so the number of positive divisors is ...
(3+1)(1+1) = 4·2 = 8
The number n has 8 different positive divisors.
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Additional comment
The divisors are ...
1, a, b, a², ab, a³, a²b, a³b
Example: 24 = 2³·3 has divisors ...
1, 2, 3, 4, 6, 8, 12, 24
