Answer:
The molarity of the solution 0.1 mol/L.
Explanation:
Molarity of the solution is defined as number of moles of substance present in one liter of solution.
[tex]Molarity=\frac{\text{Mass of compound}}{\text{Molar mass of compound}\times \text{volume of solution (L)}}[/tex]
Mass of glucose = 36.0 g
Molar mass of glucose = 180 g/mol
Volume of the solution = 2.0 L
[tex]M=\frac{36.0 g}{180 g/mol\times 2.0L}=0.1 mol/L[/tex]
The molarity of the solution 0.1 mol/L.
Based on the data provided and the formula for calculating molarity, the molarity of the glucose solution is 0.1 M.
The molarity of a solution is calculated using the formula below:
Also:
Number of moles of glucose in 36.0 g = 36.0/180
Number of moles of glucose = 0.2 moles
Then;
Molarity of the solution = 0.2/2.0
Molarity of the solution of glucose = 0.1 M
Therefore, based on the data provided, the molarity of the glucose solution is 0.1 M
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