Respuesta :
To convert grams to atoms, we first need to find the moles and then multiply by Avogadro's constant.
0.1310 g * (1 mol/22.99 g) * (6.022*10^23 atom/1 mol) = 3.431 *10^21 atoms.
0.1310 g * (1 mol/22.99 g) * (6.022*10^23 atom/1 mol) = 3.431 *10^21 atoms.
[tex]\boxed{{\text{3}}{\text{.43}}\times{\text{1}}{{\text{0}}^{{\text{21}}}}{\text{ atoms}}}[/tex] of sodium are present in 0.1310 g of sodium.
Further Explanation:
Mole is a measure of the amount of substance. It is defined as the mass of a substance that has the same number of fundamental units as there are atoms in 12 g of carbon-12. Such fundamental units can be atoms, molecules or formula units.
Avogadro’s number is the number of units that are present in one mole of substance. Its value is equal to [tex]{\text{6}}{\text{.022}}\times {\text{1}}{{\text{0}}^{{\text{23}}}}\;{\text{units}}[/tex] per mole of substance. These units can be electrons, atoms, molecules or ions.
The formula to calculate the moles of sodium is as follows:
[tex]{\text{Moles of sodium}}=\dfrac{{{\text{Given mass of sodium}}}}{{{\text{Molar mass of sodium}}}}[/tex] ......(1)
The given mass of sodium is 0.1310 g.
The molar mass of sodium is 22.9897 g/mol.
Substitute these values in equation (1).
[tex]\begin{aligned}{\text{Moles of sodium}}&=\left({{\text{0}}{\text{.1310 g}}}\right)\left({\frac{{{\text{1 mol}}}}{{{\text{22}}{\text{.9897 g}}}}}\right)\\&={\text{0}}{\text{.005698204 mol}}\\&\approx {\text{0}}{\text{.0057 mol}}\\\end{aligned}[/tex]
The number of sodium atoms is calculated as follows:
[tex]{\text{Atoms of sodium}}=\left({{\text{Moles of sodium}}} \right)\left({{\text{Avogadro's Number}}}\right)[/tex] ......(2)
The moles of sodium is 0.005698204 mol.
The value of Avogadro’s number is [tex]{\text{6}}{\text{.022}} \times{\text{1}}{{\text{0}}^{{\text{23}}}}\;{\text{atoms}}[/tex].
Substitute these values in equation (2).
[tex]\begin{aligned}{\text{Number of atoms of sodium}}{\mathbf&{ = }}\left( {{\text{0}}{\text{.005698204 mol}}}\right)\left({\frac{{{\text{6}}{\text{.022}}\times {\text{1}}{{\text{0}}^{{\text{23}}}}{\text{ atoms}}}}{{{\text{1 mol}}}}}\right)\\&={\text{3}}{\text{.43145}}\times {\text{1}}{{\text{0}}^{{\text{21}}}}{\text{ atoms}}\\&\approx {\text{3}}{\text{.43}}\times {\text{1}}{{\text{0}}^{{\text{21}}}}{\text{atoms}}\\\end{aligned}[/tex]
Therefore, the number of atoms of sodium is [tex]{\mathbf{3}}{\mathbf{.43 \times 1}}{{\mathbf{0}}^{{\mathbf{21}}}}{\mathbf{ atoms}}[/tex] .
Learn more:
1. Calculate the moles of chlorine in 8 moles of carbon tetrachloride: https://brainly.com/question/3064603
2. Calculate the moles of ions in the solution: https://brainly.com/question/5950133
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Mole concept
Keywords: sodium, atom, molecules, 0.1310 g, mole, Avogadro’s number, molar mass, given mass of sodium, 0.005698204 mol, 22.9897 g/mol, 12 g, carbon-12, amount of substance, electrons, atoms, molecules.
