Answer:
D. It is not a function.
Step-by-step explanation:
Radius of given circle = 4 units
Center = (0,0)
Equation of circle : [tex](x-h)^2+(y-k)^2 =r^2[/tex]
where (h,k) is the center
So, equation of given circle = [tex]x^2+y^2 =4^2[/tex]
Substitute x = -1
[tex](-1)^2+y^2 =4^2[/tex]
[tex]1+y^2 =16[/tex]
[tex]y=\sqrt{15}[/tex]
[tex]y=\pm 3.872[/tex]
So, since at one value of x we are getting the two values of y .
A function is a relation that for each input, there is only one output.
So, It is not a function.
Hence Option D is true.
