Well, determine the x and y components of the displacement.
Vx = (-1) + 4 = 3
Vy = 3 = 3
Then use a^2 + b^2 = c^2.
a^2 + b^2 = c^2
c = sqrt(a^2 + b^2)
c= sqrt((3)^2 + (3)^2)
c = sqrt(9 + 9)
c = sqrt(18)
c =~ 4.2 blocks Determine the angle using arctangent.
arctan(3/3) = Theta
Theta = 45 degrees north of east
(by 'Theta', I mean the angle you are wishing to find)
_Part 3_
Since distance is a scalar, simply add up all the distances.
1 + 3 + 4 = 8 blocks
