Answer:
88%
Explanation:
4 K(s) + O2(g) --> 2K2O(s)
Since Oxygen gas is said to be in excess, it means that potassium is the limiting reactant.
From the reaction above;
4 mol of K produces 2 mol of K2O
In terms of mass;
Mass = Number of moles * Molar mass
156.3752g (4mol * 39.0983g/mol) of K produces 188.3732g (2mol * 94.1866g/mol) of K2O
If 156.3752g produces 110.1856g, 162 would produce?
156.3752 = 188.3732
162 = x
Upon solving for x,
x = (162 * 188.3732) / 156.3752
x = 195.1490g
Theoretical yield = 195.1490g
But Experimental yield = 172 g
Percent yield = (Experimental Yield / Theoretical Yield) * 100
Percent Yield = (172 / 195.1490) * 100
Percent Yield = 0.8820 * 100 = 88%
